Two bicyclists head toward each other from the opposite ends of Main Street, which is six miles long. The first biker started at 2:05 going 12 mph. The second biker began peddling 4 minutes later at a rate of 14 mph. What time will they meet?

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Accepted Answer

The first bike got a 4/5 mile head start (12 × 4/60). Therefore, by the time the second bike leaves, there are 51/5 miles between them (6 4/5). Their combined rate of travel is 12 + 14 = 26 mph. Lett= the number of hours the second bike travels. 26t= 51/5 26t= 26/5 t= 26/5 ÷ 26/1 t= 26/5 × 1/26 t= 1/5 1/5 of an hour = 20 minutes. The second bike left at 2:09, so both bikes will meet at 2:29.

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