There are 12 liters of a mixture of acetone in alcohol that is 33 % acetone. 1 low many liters of alcohol must be added to the mixture to reduce it to a mixture containing 25% acetone?

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If the original mixture is 33 % (or 1/3) acetone, then 1/3 of the mixture of 12 liters, or 4 liters, is acetone. The fraction 4/12 represents the ratio of acetone to total mixture. If the total mixture is increased by x liters, the ratio of acetone to total mixture becomes 4/(12+x).This is to be equal to 25% (or 1/4). 4 / 12+x = 1 / 4 To undo the divisions on both sides of the equation, multiply both sides by 4 and also by 12+x. 4/12+x * 4(12+x)/1 = 1/4 * 4(12+x)/1 16 = 12+x The isolate x on one side of the equation, subtract 12 from both sides 16-12 = 12 + x-12 4=x

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