Four squares are joined together to form one large square. If the perimeter of one of the original squares was 8x units, what is the perimeter of the new, larger square?

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The perimeter of each small square is 8x units; therefore, the length of a side of each small square is 8x ⁄ 4 = 2x units. Since the new, large square is comprised of two sides from each of the four squares (the remaining four sides are now within the large square), the perimeter of the new, large square is equal to: 4(2x + 2x) = 4(4x) = 16x units.

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